https://leetcode.cn/problems/binary-tree-zigzag-level-order-traversal/description/
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题解:https://leetcode.cn/problems/binary-tree-zigzag-level-order-traversal/solutions/530400/er-cha-shu-de-ju-chi-xing-ceng-xu-bian-l-qsun/
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func zigzagLevelOrder(root *TreeNode) (ans [][]int) {
if root == nil {
return
}
queue := []*TreeNode{root}
for level := 0; len(queue) > 0; level++ {
vals := []int{}
q := queue
queue = nil
for _, node := range q {
vals = append(vals, node.Val)
if node.Left != nil {
queue = append(queue, node.Left)
}
if node.Right != nil {
queue = append(queue, node.Right)
}
}
// 本质上和层序遍历一样,我们只需要把奇数层的元素翻转即可
if level%2 == 1 {
for i, n := 0, len(vals); i < n/2; i++ {
vals[i], vals[n-1-i] = vals[n-1-i], vals[i]
}
}
ans = append(ans, vals)
}
return
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