https://leetcode.cn/problems/binary-tree-zigzag-level-order-traversal/description/
func zigzagLevelOrder(root *TreeNode) (ans [][]int) { if root == nil { return } queue := []*TreeNode{root} for level := 0; len(queue) > 0; level++ { vals := []int{} q := queue queue = nil for _, node := range q { vals = append(vals, node.Val) if node.Left != nil { queue = append(queue, node.Left) } if node.Right != nil { queue = append(queue, node.Right) } } // 本质上和层序遍历一样,我们只需要把奇数层的元素翻转即可 if level%2 == 1 { for i, n := 0, len(vals); i < n/2; i++ { vals[i], vals[n-1-i] = vals[n-1-i], vals[i] } } ans = append(ans, vals) } return